Which expression verifies that a unit vector u = (a,b,c) has magnitude 1?

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Multiple Choice

Which expression verifies that a unit vector u = (a,b,c) has magnitude 1?

Explanation:
The key idea is how we measure the length of a vector in three dimensions. The length (magnitude) of a vector (a, b, c) is given by the Euclidean norm, which strips out the square roots of the sums of squares of its components: |u| = sqrt(a^2 + b^2 + c^2). For a unit vector, this length must be 1, so we would have sqrt(a^2 + b^2 + c^2) = 1, meaning a^2 + b^2 + c^2 = 1. The expression that directly gives the magnitude in terms of a, b, and c is sqrt(a^2 + b^2 + c^2), making it the correct form to verify unit length. The other forms don’t represent the magnitude in terms of the components: without the square root, you get the squared length; summing the components a + b + c isn’t related to length in general; and simply stating |u| = 1 does describe the unit length but doesn’t express the magnitude in terms of a, b, and c.

The key idea is how we measure the length of a vector in three dimensions. The length (magnitude) of a vector (a, b, c) is given by the Euclidean norm, which strips out the square roots of the sums of squares of its components: |u| = sqrt(a^2 + b^2 + c^2).

For a unit vector, this length must be 1, so we would have sqrt(a^2 + b^2 + c^2) = 1, meaning a^2 + b^2 + c^2 = 1. The expression that directly gives the magnitude in terms of a, b, and c is sqrt(a^2 + b^2 + c^2), making it the correct form to verify unit length.

The other forms don’t represent the magnitude in terms of the components: without the square root, you get the squared length; summing the components a + b + c isn’t related to length in general; and simply stating |u| = 1 does describe the unit length but doesn’t express the magnitude in terms of a, b, and c.

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