Decompose (3x+4)/(x^2 - 1) into A/(x-1) + B/(x+1). What are the values of A and B?

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Multiple Choice

Decompose (3x+4)/(x^2 - 1) into A/(x-1) + B/(x+1). What are the values of A and B?

Explanation:
Partial fraction decomposition expresses the fraction as a sum of simpler fractions, using that x^2 − 1 factors as (x − 1)(x + 1). Set (3x + 4)/(x^2 − 1) = A/(x − 1) + B/(x + 1). Combining the right-hand side gives [A(x + 1) + B(x − 1)]/[(x − 1)(x + 1)]. Matching numerators: (A + B)x + (A − B) = 3x + 4 So A + B = 3 and A − B = 4. Solving, A = 7/2 and B = 3 − A = 3 − 7/2 = −1/2. Check: (7/2)(x + 1) + (−1/2)(x − 1) = 3x + 4, confirming the decomposition. Therefore A = 7/2 and B = −1/2. The other options fail because they do not satisfy both A + B = 3 and A − B = 4.

Partial fraction decomposition expresses the fraction as a sum of simpler fractions, using that x^2 − 1 factors as (x − 1)(x + 1).

Set (3x + 4)/(x^2 − 1) = A/(x − 1) + B/(x + 1). Combining the right-hand side gives [A(x + 1) + B(x − 1)]/[(x − 1)(x + 1)]. Matching numerators:

(A + B)x + (A − B) = 3x + 4

So A + B = 3 and A − B = 4. Solving, A = 7/2 and B = 3 − A = 3 − 7/2 = −1/2.

Check: (7/2)(x + 1) + (−1/2)(x − 1) = 3x + 4, confirming the decomposition.

Therefore A = 7/2 and B = −1/2. The other options fail because they do not satisfy both A + B = 3 and A − B = 4.

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